Question

A diver jumps from a height of 2m with initial velocity of 4.5m/s, Calculate the time for which the diver is in the air.

Answer 1

Answer:

0.44 sec

Explanation:

Time = Distance /Velocity

Distance= 2m

Initial Velocity= 4.5m/s

Time = 2/4.5

Time = 0.44 sec

Hope u understood

Answer 2

Answer:

v=u+at

a=+g

u=4.5 m/s

v^2-u^2=2as

v^2=u^2+2gh

(4.5)^2+9. 8 * 2

(4.5*4.5) + 9.8 * 2

v^2=59.45

v=7.7

7.7=4.5+9.8*t

t*9.8=3.2

t=3.2/9.8

=0.3