Physics, asked by syedaffan1721, 16 days ago

A diver jumps from a height of 2m with initial velocity of 4.5m/s, Calculate the time for which the diver is in the air.

Answers

Answered by aditi200758
0

Answer:
Time = Distance /VelocityDistance= 2mInitial Velocity= 4.5m/sTime = 2/4.5Time = 0.44 sec

Explanation:

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