Question

A diverging mirror produces two times magnified (enlarged) virtual image of
an object placed at 10 cm in front of it. Where is the image located?​

Answer 1

Explanation:

m= +3

Object Distance = u= -10cm( sign conventions)

V=?

Formula to be used:m= -V/u

V= -m x u

= -3×-10

=30 cms

Now to find focal length , Let us use mirror formula:

1/f = 1/v + 1/u

1/f = 1/30 -1/10

=1-3/30

=-2/30

=-1/15

f = -15cms.

The object is placed between P and F and we get virtual , enlarged and erect image.

Radius of curvature = 2f

= 2x-15

=-30cms.

Answer 2

Answer:

Given:

m= +3

Object Distance = u= -10cm( sign conventions)

V=?

Formula to be used : m= -V/u

V= -m x u

= -3×-10

=30 cm's

Now to find focal length , Let us use mirror formula:

1/f = 1/v + 1/u

1/f = 1/30 -1/10

=1-3/30

=-2/30

=-1/15

f = -15cms.

The object is placed between P and F and we get virtual , enlarged and erect image.

Radius of curvature = 2f

= 2x-15

= -30cm's.