A divers descends 20 feet in the water from the boat at the surface of a lake . he then rose 12 feet and descends another 18 feet .at this point what is his depth in water?
Answers
Answer:
Let the initial position of the diver be 0.
Now, the diver descends 20 feet in the water which can be given as -20 feets.
Then he rose 12 feet i.e. +12 feets and he descends another 18 feet i.e. -18 feets.
Now his depth in water = final position = (-20 +12 -18) feets = -26 feets
Therefore, the man is now at 26 feet below the surface of the lake.
D 26 feet below the surface of the lake.
Answer:
Let the initial position of the diver be 0.
Now, the diver descends 20 feet in the water which can be given as -20 feets.
Then he rose 12 feet i.e. +12 feets and he descends another 18 feet i.e. -18 feets.
Now his depth in water = final position = (-20 +12 -18) feets = -26 feets
Therefore, the man is now at 26 feet below the surface of the lake.
D 26 feet below the surface of the lake.
Explanation: