Question

A divers descends 20 feet in the water from the boat at the surface of a lake . he then rose 12 feet and descends another 18 feet .at this point what is his depth in water?​

Answer 1

Answer:

Let the initial position of the diver be 0.

Now, the diver descends 20 feet in the water which can be given as -20 feets.

Then he rose 12 feet i.e. +12 feets and he descends another 18 feet i.e. -18 feets.

Now his depth in water = final position = (-20 +12 -18) feets = -26 feets

Therefore, the man is now at 26 feet below the surface of the lake.

D 26 feet below the surface of the lake.

Answer 2

Answer:

Let the initial position of the diver be 0.

Now, the diver descends 20 feet in the water which can be given as -20 feets.

Then he rose 12 feet i.e. +12 feets and he descends another 18 feet i.e. -18 feets.

Now his depth in water = final position = (-20 +12 -18) feets = -26 feets

Therefore, the man is now at 26 feet below the surface of the lake.

D 26 feet below the surface of the lake.

Explanation:

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AKRITI❤️