Question

A Diwali rocket, when ignited at the ground level, rises vertically upwards to the level of
a window 10 m from the ground. Find the magnitude of velocity of the rocket at the time
of its take off.​

Answer 1

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Answer 2

Answer:10√2 m/sec

Explanation: a= -10m/sec² ( because acceleration is in the opposite direction of motion)

v=0(because at the max height velocity is zero)

By third equation of motion,

v²- u² = 2as

-u²=2×-10×10

u²=200

u=√200

u=10√2 m/sec

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