A doctor believes that the proportions of births in this country on each day of the
week are equal. A simple random sample of 700 births from a recent year is
selected, and the results are below. At significance level of 0:01, is there enough
evidence to support the doctor's claim? (Use Chi Test)
Answers
Answer:
Day Sunday Monday Tuesday Wednesday Thursday Friday Saturday
Frequency 65 103 114 116 115 112 75
(i) The null hypothesis H0:the population frequencies are equal to the expected frequencies
(to be calculated below).
(ii) The alternative hypothesis, Ha: the null hypothesis is false.
(iii) α = 0.01.
(iv) The degrees of freedom: k − 1 = 7 − 1 = 6.
(v) The test statistic can be calculated using a table:
Step-by-step explanation:
Day E O O − E (O − E)
2 (O−E)
2
E
Sunday 700/7 = 100 65 −35 1225 12.25
Monday 700/7 = 100 103 3 9 0.09
Tuesday 700/7 = 100 114 14 196 1.96
Wednesday 700/7 = 100 116 16 256 2.56
Thursday 700/7 = 100 115 15 225 2.25
Friday 700/7 = 100 112 12 144 1.44
Saturday 700/7 = 100 75 −25 625 6.25
χ
2 =
X ( observed − expected )2
expected =
X (O − E)
2
E
= 26.8.
(vi) From α = 0.01 and k − 1 = 6, the critical value is 16.812.
(vii) Is there enough evidence to reject H0? Since χ
2 ≈ 26.8 > 16.812, there is enough
statistical evidence to reject the null hypothesis and to believe that the proportion of
births is not the same for each day of the week.