Question

A doctor has prescribed a corrective lens of power +1.5D.Find the focal length of the lens. Is the prescribed lens diverging or converging?​

Answer 1

Explanation:

P = +1.5 D

f = 1/P = 1/+1.5 = 0.67 m.

As the power of lens is (+ve), the lens is converging lens.

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Answer 2

Answer:

$The \: power \: of \: this \: lens \: is \: positive , \\ therfore, \: this \: is \: a \: convex \: lens \: or \: \\ converging \: lens. \: now, \\ Power, p = \frac{1}{f(in \: metrs)} \\ so \: \: \: \: \: + 1.5 = \frac{1}{f} \\ or \: \: \: f = \frac{1}{ + 1.5} \: m \\ f = + \frac{1}{1.5} \times 100cm \\ \\ So, \: \: \: focal \: length \: of \: lens \: f = + \: 66.7cm$