Question

A doe is thrown once find of getting a number more than 3

Answer 1

A die can be thrown once in 6 ways
n=6
E be event of getting a number greater than E=(4, 5,6)
m=3
Probability of success =m/n=3/6=1/2

Answer 2

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Number of possible outcome = 6
probality of getting a number more than 3 means $\bold{4,5,6}$
So,
Number of favourable outcomes = 3

probality = No. of favourable outcomes / No. of possible outcomes
=3/6
=1/2

So, when a die is thrown once it's probality of getting a number more than 3 is 1/2.

Hope it helps