Question

A does 1/5th of a work in a week.B finishes teh same in a fortnight.B syarts the work and works only for 3 days.There after a completes the job.He will finish it in

Answer 1

A completes the job in 28 days.

To find : Time taken by A to finish his work.

Given :          

A does 1/5th of a work in a week    

A = $\frac{1}{5}$  of work  in a week ⇒ 7 × 5 = 35 days.

A finishes his work = 7 × 5 = 35 days.                                

B finishes the same work in 15 days.

B starts the work and works only for 3 days ⇒ $\frac{3}{15}= \frac{1}{5}$          

Remaining work = 1 - $\frac{1}{5}$ = $\frac{5-1}{5}$ $= \frac{4}{5}$

Time taken by A = 35 × $\frac{4}{5}$ = 7 × 4 = 28.      

Therefore, A finishes the remaining work in 28 days.

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Answer 2

Answer:

The rest of work is done by A in 33 $\dfrac{1}{2}$ days

Step-by-step explanation:

Given as :

A does $\dfrac{1}{5}$ th of work in 7 days

B dose  $\dfrac{1}{5}$ th of work in 14 days

So, In 14 days work done by B  = $\dfrac{1}{5}$ th

Or, In 3 days work done by B = $\dfrac{3}{70}$ th

Amount of work left =  1 -  $\dfrac{3}{70}$ th

I.e Amount of work left = $\dfrac{70 - 3}{70}$

Or, Amount of work left = $\dfrac{67}{70}$ th

∵ A does $\dfrac{1}{5}$ th of work in 7 days

So, $\dfrac{67}{70}$ th of work done by A in 35 × $\dfrac{67}{70}$

i.e  $\dfrac{67}{2}$ days

Hence, The rest of work is done by A in 33 $\dfrac{1}{2}$ days  Answer