Question

A does 4/5th of a work in 20 days. He then assembles in B and they complete the remaining work in 3 days. To what extent B alone would take to do the entire work?

Answer 1

Answer:

37.5

Step-by-step explanation:

A does 4/5 of the work in 20 days, or he would take (5/4)*20 = 25 days to do the whole work, alone.

A does (1/25)th of the work in 1 day.

A and B do (1/5)th of the work in 3 days. Or A and B, together, do (1/15)th of the work in 1 day.

So, B alone does (1/15)-(1/25) = (25–15)/(15x25) = 10/375 = 2/75th of the work in a day.

Thus, B alone will do the whole work in 37.5 days.

Answer 2

Answer:

correct answer

1/5 of a work

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thanks for question