Math, asked by reshma8032, 3 months ago

A does 7/18 of a work in 14days. Then he completes the remaining work with
the help of B in 10 days. In how many days can B alone do the work?​

Answers

Answered by ItzBrainlyGirl024
6

Answer:

A completes 7/10 of a work in 14 days, means A's daily performance is...

7/10 divided by 14 = 1/20 part of the work or A can complete the work in 20 days.

After 14 days the unfinished work left is...

1 - 7/10 = 3/10 part and A and B jointly completed this part in 2 days.

A had contributed 1/20 x 2 = 2/20 or 1/10 part and B's contribution is... The rest i.e..

3/10 - 1/10 =2/10 in 2 days or B's daily contribution is 1/10 part of the work. Therefore B Alone could have completed the work in...

10 days. Answer.

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION

Answered by bhartirathore299
1

Answer:

10 days

hope so it will helpful to you

Attachments:
Similar questions