Math, asked by ashu5439, 10 months ago

a does 8/ 15 of the given work in 8 days and remaining work is finish with the assistance of B in 4 days how long will b
to take the work alone​

Answers

Answered by Anonymous
28

Answer :-

B alone takes 20 days to complete the work.

Explanation :-

In 8 days A completes = (8/15) of the given work

In 1 day A completes = (8/15) ÷ 8 = (8/15) × (1/8) = 1/15 of the given work

i.e A's 1 day work = 1/15

Remaining work done by A with the assistance of B = 1 - Work done by A in 8 days

= 1 - (8/15)

Taking LCM

= (15 - 8)/15

= 7/15

i.e Remaining work done by A with the assistance of B = 7/15

Given

Remaining work is finished by A with the assistance of B in 4 days

We know that

Number of Days worked × (A's 1 day work + B's 1 day work) = Remaining work done by A with the assistance of B

⇒4(1/15 + B) = 7/15

⇒ (1/15) + B = (7/15) ÷ 4

(1/15) + B = (7/15) × (1/4)

⇒ (1/15) + B = 7/60

⇒ B = (7/60) - (1/15)

Taking LCM

⇒ B = (7 - 4)/60

⇒ B = 3/60

⇒ B = 1/20

i.e B's 1 day work = 1/20

So B alone takes 20 days to complete the work.

Answered by akratigupta550
0

Answer:

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