Math, asked by sheetal411, 10 months ago

A does a work in 10 days and B does work 8n 15 days both together meets in how much days they completed
same work​

Answers

Answered by debrajdb15901121
0

Step-by-step explanation:

what is your question I didn't understandyou telling

Answered by Anonymous
3

Answer

6 days is the required answer.

Important formula related to above question

If A can do work in D1 and b can do same work in D2 days , then A and B can together do the same work in

D1×D2/D1+D2 days

Given

==>

A can do work = 10 Days

B can do work = 15 days.

Solution

==>

A and b working together then formula used =

 \frac{d1 \times d2}{d1 + d2}

Calculation

 \frac{10 \times 15}{10 + 15}

 \frac{150}{25}

6 days

Important relations

↗Work and person are directly proportional.

↗Time and person are inversely proportional

↗Work and Time are directly proportional.

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