Question

A does a work in 16 days and b does the work in 12 days ,b together with a boy does the same work in 8 days .How much time will be the boy alone take to do the work?

Answer 1

Answer:

Step-by-step explanation:

According to question;

A does piece of work =16 days (alone)

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B does that work=12 days (alone)

When B does that work with boy it was completed in eight days(8)

........

So ;

One day work of both =1/8;

B does that work in 12 days so one day work of B =1/12

B+boy=8

B and boy together did work in 8 days;

So frame equation in one day form;

1/12+Boys work=1/8

Boy=1/8-1/12

Boy=3-2/24

BOY=1/24

SO ONE DAY WORK OF BOY IS 1/24 ;

SO TOTAL TIME TAKEN BY BOY ALONE TO DO THAT WORK IS 24 Days.

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Answer 2

Answer

One day work of:

A = 1/16

B = 1/12

B+Boy = 1/8

Now, B+Boy = 1/8

=> 1/12 + Boy = 1/8

=> Boy = 1/8 - 1/12

=> Boy = 3-2/24

=> Boy = 1/24

Boy takes = 24 days