Question

a does a work in 6 days b day 8 day and c in 10 days .a worked alone for 2 days before leaving and then b and c worked together for 2 days and after b left .the remaining work was finished by c alone .how long did it take to finish the work​

Answer 1

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Step-by-step explanation:

A and B work together for 2,5/10 = 25% of the job

B then works an extra 6 days at which time 40% is complete. This implies that B did (40–25) 15%

so if B does 15% in 6 days he completes the job in

6/15/100 = 40 days

since A and B work together to complete in 10 days

1/A + 1/40 = 1/10

1/A = 0,075

A = 13,333 days

B = 40 days