Math, asked by muralimrv23, 1 month ago


A does half as much work as B and C does half as much work as A and B
together. If C alone can finish the work in 40 days, then together all will finish
the work in:
A. 13 and 1/3 days B.20 days C.15 days D.30 days
8 A can dol​

Answers

Answered by ItzMissKomal
1

Answer:

As given C does half as much work as A and B together

=> (A + B) can do it in 20 days

(A + B)s 1 days wok = 1/20.

A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)

A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]

B's 1 days work = (1/20) x (2/3) = 1/30

(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40

All the three together will finish it in 40/3 = 13 and 1/3 days.

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