Question

A dog barks in a park and hears its echo after 0.5 seconds. The sound of speed in air is 340 m/s. The
distance between the dog and the building is

Answer 1

The formula to tabulate the answer is: 2s= V x T where s is the displacement ; V is the velocity and T is the time. So according to the question, we get 2 x S

The formula to tabulate the answer is: 2s= V x T where s is the displacement ; V is the velocity and T is the time. So according to the question, we get 2 x S= 346 x 0.5. So S = 346 = 2 x 0.5. So we get the answer 86.5 metres

Answer 2

Answer:

86.5 m

Explanation: