Question

A dog barks infront of a cliff and an echo is heard 4s later . If the speed of sound is 340 m/s . Calculate the distance of the cliff from the dog​

Answer 1

Explanation:

$echo = v = \frac{2d}{t}$

$340 = \frac{2 \times y}{4}$

$\frac{340 \times 4}{2} = y$

$y = 680m$