Question

A dog is chasing a cat. The cat is running with constant velocity u = 10ms and the dog is running
with constant speed v=30ms At an instant direction of motion of the dog makes an angle 30° with that of the cat and the distance between them is r=50m. The magnitude of
acceleration of the dog at that instant in m/s^2
is​

Answer 1

Answer:

9m/s^2

Explanation:

s=v^2/2a

50=(30)^2/2a

100=900/a

a=900/100

a=9m/s^2

Answer 2

Given:

u = 10m/s

v =30m/s

angle = 30°

r = 50m   (let r be equal to s)

To find : magnitude at that time in m/s²

Explanation:

According to the question dog is running with constant speed

   speed = (total length of the path/ time taken to cover that distance)

∴ Relative to ground the acceleration is zero since he is running with constant speed

                                 S = v²/2a

                               50 = (30²) / 2a

                              100 = 900/a

                                  a = 900/100

                                  a = 9m/s²

Answer =  9m/s²