a dog ran 100 m in 20 sec he then comes bck half the distance in 10 sec and stops what is the dogs average velocity
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Answer:
Given,
In first event, displacement S=200m in time t
1
=25sec
In second event, displacement S=−100m in time t
1
=15sec
Average velocity=
total time
Total displacement
=
t
1
+t
2
S+(−S)
=
25+15
200+(−100)
=2.5ms
−1
Average speed=
total time
Total distance
=
t
1
+t
2
S+S
=
25+15
200+100
=10ms
−1
Hence, Average velocity 2.5ms
−1
and average speed is 10ms
−1
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