Question

A dog running at 3.2m/s speeds up to 5m/s over a 4s period. What is its acceleration?

Answer 1

$using\: V=u+at\\5=3.2+a(4)\\5-3.2=4a\\1.8=4a\\a=0.45ms{}^{-2}$

Answer 2

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usingV=u+at

5=3.2+a(4)

5−3.2=4a

1.8=4a

a=0.45ms

−2