Question

a dog running at a speed of 2 metre per second accelerates at a constant rate of 1.5 metres per second square for 5 seconds calculate the distance covered with a dog and final velocity of the dog​

Answer 1

Answer:

Explanation:

Use the basic laws to derive..

Here is the solution

Answer 2

Explanation:

Inital speed of dog =2m/s

a=1.5m/s square

t=5 sec

Final velocity,

V=u+at (first equation of motion)

=2+1.5×5

=2+7.5

=9.5m/s.

Distance covered by cat=?

v=d÷t

D= V2×t

=9.5×5

= 47.5m

Therefore,the final speed is 9.5m/s and distance covered by dog is 47.5 m.

I Hope it will help you.