A dog runs 120 m away from its master in a straight line in 9.0s, and then runs halfway back in
one third the time. Calculate its average speed
(A) 10m/s
(B) 15m/s
(C) 20m/s
(D) 5m/s
Answers
Answered by
0
Answer:
d1=120 d2=60m t1=9s t2=3s
As= 120+60/9+3=180/12=45/3=16
Answered by
2
Answer:
Hey mate
your answer is option "b"
15m/s
Explanation:
distance 1 = 120m
time 1 = 9s
distance 2 = 60m
time 2 = ⅓ × 9 = 3
average speed = distance/time
speed = 120 + 60
9 + 3
speed = 180/12
speed = 15m/s
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