Question

A dog runs 150 m away from his master in straight line in 10 seconds and then returns halfway back in one-fourth the time. Calculate its average velocity:-

Answer 1

Given : A dog runs 150 m away from his master in straight line in 10 seconds and then returns halfway back in one-fourth the time.

To Find : Average velocity:

A ) 10 ms-1 B) 6 ms-1 C 15 ms-1 D) 21 ms-1

Solution:

dog runs 150 m away in 10 secs

Displacement  = Final position - Initial Position

Velocity = Displacement ./ Time

go away = 150 m

returns halfway back = 150/2 = 75 m

Net Distance from original position = 150 m - 75 m = 75m

Displacement = 75 m

Time in going = 10 sec

Time in return = 10/4 = 2.5 sec

Total Time = 10 + 2.5  = 12.5 secs

Velocity = 75/12.5  = 6 m/s

Average velocity = 6 m/s

Correct option is B

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Answer 2

Question :-

A dog runs 150 m away from his master in straight line in 10 seconds and then returns halfway back in one-fourth the time. Calculate its average velocity:-

Answer :-

• 6m/s

Step by step explanation :-

We know that,

$\tt:\longmapsto{Velocity = \frac{Displacement}{Time}}$

And,

$\tt:\longmapsto{Displacement = final \:position - initial \: position}$

Now,

Go away = Initial position = 150m

returns halfway back(given) = Final position = $\frac{150}{2}$ = 75m

Now, displacement becomes

$\rm\longrightarrow{ Displacement= 150 - 75 = 75m}$

Now, time is

Going time = 10s (given)

Returning time = one-fourth of going time

Then,

Returning time =

$\longrightarrow \frac{10}{4}$ = 2.5s

Total time = 10 + 2.5 = 12.5s

Average velocity is equals to,

$\rm\longrightarrow{Average \: velocity = \cancel \frac{75}{12.5} } \\ \\ \rm\longrightarrow{Average \: velocity =6 m/s}$

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