Question

A dog takes 6 leaps for every 4 leaps of a hare and 2 leaps of the
dog are equal to 5 leaps of the hare. What is the ratio of their speed ?​

Answer 1

Answer:

Let hare take 20 leaps in 1 second.

Hence dog will take 30 leaps in one second.

Now , The distance traveled by hare in 1 leap= 2/5 that of dog.

Distance in1 second = 20 leap of hare = 30×5/2 of dog = 75

Hence ratio of speed is

20/75

4/15 for hare: dog.

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Answer 2

The ratio of speeds of dog and hare is 15:4.

Given:

A dog takes 6 leaps for every 4 leaps of a hare.

2 leaps of the dog are equal to 5 leaps of the hare.

To Find:

We have to find the ratio of their speed.

Solution:

Let us assume the dog takes 6 leaps in 1 second.

Therefore the dog takes 1 leap in $\frac{1}{6}$ seconds.

So, for two leaps the time taken is $\frac{2}{6}$ = $\frac{1}{3}$ seconds.

Next, we take the example of the hare. Now it takes 4 leaps for dogs every 6 leaps.

So in the same time, i.e., in 1 sec it will take 4 leaps.

The hare takes 4 leaps in 1 second.

The hare takes 1 leap in $\frac{1}{4}$ seconds.

So, it will take 5 leaps in $\frac{5}{4}$ seconds

So speed = distance upon time.

The ratio of their speed is,

Speed of dog: Speed of hare

=  (1m/ $\frac{1}{3}$ sec) / (1m / $\frac{5}{4}$ sec).

Hence, the ratio of speeds of dog and hare is 15:4.

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