A dome of a building is in the form of a hemisphere from inside it was White wash at the cost of rupees £4.98. 96 if the cost of whitewashing is @ rupees 2 per square metre find the inner surface area of the Dome
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(i) Cost of white-washing the dome from inside = Rs 498.96
Cost of white-washing 1 m2 area = Rs 2
Therefore, CSA of the inner side of dome =
= 249.48 m2
(ii) Let the inner radius of the hemispherical dome be r.
CSA of inner side of dome = 249.48 m2
2πr2 = 249.48 m2

⇒ r = 6.3 m
Volume of air inside the dome = Volume of hemispherical dome

= 523.908 m3
= 523.9 m3 (approximately)
Therefore, the volume of air inside the dome is 523.9
Cost of white-washing 1 m2 area = Rs 2
Therefore, CSA of the inner side of dome =
= 249.48 m2
(ii) Let the inner radius of the hemispherical dome be r.
CSA of inner side of dome = 249.48 m2
2πr2 = 249.48 m2

⇒ r = 6.3 m
Volume of air inside the dome = Volume of hemispherical dome

= 523.908 m3
= 523.9 m3 (approximately)
Therefore, the volume of air inside the dome is 523.9
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