A dominant gene K in mice produces a kinked tail;recessive genotypes at this locus kk have normal tails.The homozygous condition at another locus AA produces a gray colour agouti;the heterozygous condition AyA produces yellow colour;the homozygous genotype AyAy is lethal.
a).If yellow mice heterozygous kinky tail,are crossed together,what phenotypic proportions are expected in their offsprings?
b.What proportion of the offspring is expected to be of genotype AyAKk?
c.if all the yellow offsprings were to mate at random,what would be the genotypic and phenotypic ratios among their adult progeny?
Answers
Answer:
A dominant gene K in mice produces a kinked tail;recessive genotypes at this locus kk have normal tails.The homozygous condition at another locus AA produces a gray colour agouti;the heterozygous condition AyA produces yellow colour;the homozygous genotype AyAy is lethal.
a).If yellow mice heterozygous kinky tail,are crossed together,what phenotypic proportions are expected in their offsprings?
b.What proportion of the offspring is expected to be of genotype AyAKk?
c.if all the yellow offsprings were to mate at random,what would be the genotypic and phenotypic ratios among their adult progeny?
a) 1 yellow kinky tail : 1 grey colour agouti with kinky tail.
b) 1:1
c) Ratio of adult progeny phenotype. 1 gray colour agouti: 2 yellow colour
Adult progeny Genotype ratios= 1 AA: 2 AAy: AyAy out of 75% result because 25% chances of lethal gene carrying would die.
Explanation:
a) yellow mice have genotype of AyA
Kinky tail KK
The punnet square shows
A Ay
K AK AyK
k Ak Ayk
Genotype ratio i= 1:1:1:1
phenotype will be 1 yellow kinky tail : 1 yellow normal tail: 1 gray normal tail:1 gray kinky tail.
b) Genotype ratio = 25% will have AyK and 25% will have Ak.
c) If yellow offspring randomly mate then
A Ay
A AA AAy
Ay AAy AyAy
1 gray colour agouti: 2 yellow colour: 1 lethal
Genotype ratios= 1 AA: 2 AAy: AyAy AyAy is lethal so adult of this would not survive.
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