a donor agency decided to supply milk to the recent flood affected people in the campus the container is made up of metal sheet which is in the form of a frustum of a cone cylinder at both ends after the milk is filled the height of the container is 16 cm with radii of the lower and upper ends 8 cm and 20 CM respectively find the cost of milk which can completely filled the container @ rupees 15 per litre and the cost of metal sheet required to make the container at the rate of rupees 5 per 100 cm square use pi 3.14
Answers
Milk Cost = Rs 156.75 , cost of metal sheet 160.77 Rs
Step-by-step explanation:
R = 20 cm
r = 8 cm
h = 16 cm
Volume = (1/3) π h (R² + r² + R.r)
=> V = (1/3) (3.14) (16) ( 20² + 8² + 20*8)
=> V = (50.24/3) (400 + 64 + 160)
=> V = (50.24/3) (624)
=> V = 50.24 * 208
=> V = 10449.92 cm³
1000 cm³ = 1 litre
Milk = 10.4499 litre
rupees 15 per litre
Milk Cost = 15 * 10.4499 = Rs 156.75
Surface Area = π(R + r)( √(R-r)² + h²) + πR² + πr²
= (3.14) (20 + 8) (√(20-8)² + 16²) + (3.14)20² + (3.14)8²
=(3.14) (28) (20) + (3.14)( 400 + 64)
= (3.14)(560 + 464)
= (3.14)(1024)
= 3215.36 cm²
metal sheet required to make the container at the rate of rupees 5 per 100 cm ²
= 5 * 3215.36 /100
= 160.77 Rs
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Answer:
Milk Cost = Rs 156.75 , cost of metal sheet 160.77 Rs
Step-by-step explanation:
R = 20 cm
r = 8 cm
h = 16 cm
Volume = (1/3) π h (R² + r² + R.r)
=> V = (1/3) (3.14) (16) ( 20² + 8² + 20*8)
=> V = (50.24/3) (400 + 64 + 160)
=> V = (50.24/3) (624)
=> V = 50.24 * 208
=> V = 10449.92 cm³
1000 cm³ = 1 litre
Milk = 10.4499 litre
rupees 15 per litre
Milk Cost = 15 * 10.4499 = Rs 156.75
Surface Area = π(R + r)( √(R-r)² + h²) + πR² + πr²
= (3.14) (20 + 8) (√(20-8)² + 16²) + (3.14)20² + (3.14)8²
=(3.14) (28) (20) + (3.14)( 400 + 64)
= (3.14)(560 + 464)
= (3.14)(1024)
= 3215.36 cm²
metal sheet required to make the container at the rate of rupees 5 per 100 cm ²
= 5 * 3215.36 /100
= 160.77 Rs