Math, asked by Ta9, 1 year ago

A donor agency ensures milk is supplied in containers which are in the form of frustum of a cone to be distributed to food victims in a camp. The height of each frustum is 30 cm and the radii of whose lower and upper circular ends are 20 cm and 40cm respectively. If this milk is available at the rate of RS. 35 per litre and 880litres of milk is needed daily for a camp

Answers

Answered by nikitasingh79
170
Given:
Radius of the lower end of the container(r) = 20 cm
Radius of the bigger end of the container( R) = 40 cm
Height of the container(h) = 30 cm
Capacity of container = 1/3πh[R² + r² + Rr]
=1/3×22/7×30×[(40)² +(20)²+40×20]
=1/3×22/7×30×[1600 +400 +800]
=1/3×22/7×30×[2800]
=22×10×[400]
=88000 cm³
= 88000/1000
=88 litres
[1000 cm³ = 1 litres]
Amount of milk needed by the camp daily = 880 litres
Hence, number of containers needed = 880/88 = 10
cost of 1 litre milk = ₹35
Cost of 880 litres of milk = ₹ (35 × 880) =₹ 30800

HOPE THIS WILL HELP YOU...
Answered by glakshmijaya
29

Answer:

Given:

Radius of the lower end of the container(r) = 20 cm

Radius of the bigger end of the container( R) = 40 cm

Height of the container(h) = 30 cm

Capacity of container = 1/3πh[R² + r² + Rr]

=1/3×22/7×30×[(40)² +(20)²+40×20]

=1/3×22/7×30×[1600 +400 +800]

=1/3×22/7×30×[2800]

=22×10×[400]

=88000 cm³

= 88000/1000

=88 litres

[1000 cm³ = 1 litres]

Amount of milk needed by the camp daily = 880 litres

Hence, number of containers needed = 880/88 = 10

cost of 1 litre milk = ₹35

Cost of 880 litres of milk = ₹ (35 × 880) =₹ 30800

HOPE THIS WILL HELP YOU...

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