Math, asked by nandani86, 1 year ago

A door 2.1 X 1m is fitted in a wall. length of the wall is 6.5 m and the height is 4 m find the cost of plastering the wall if the rate of plastering the wall is ₹ 10 per m2

Answers

Answered by Anonymous
27

Answer:

239

Step-by-step explanation:

Length of door = 2.1 m , breadth of door = 1 m.

Area of door = length * breadth

                     = 2.1 * 1

                     = 2.1 m²



Length of wall = 6.5 m, breadth of wall = 4 m.

Area of wall = 6.5 * 4

                    = 26 m²


Area of wall including door - Area of wall

= 26 - 2.1

=  23.9 m²


The cost of plastering the wall per m² = 10.

The rate of plastering the wall 23.9 per m² = 10 * 23.9

= 239.


Hope it helps you.

#Bebrainly



Answered by nethranithu
14

hey there


here ur answer


Given:

Length of door  = 2.1 m

1st breadth of door = 1 m.

Length of wall         = 6.5 m

breadth of wall        = 4 m.


Solution:


Calculating for door:


Area of door = length × breadth

                     = 2.1 × 1

                     = 2.1 m²


thn,


Calculation for wall :


Area of wall = length × breadth

                   = 6.5 × 4

                   = 26 m²


So,


→  26 - 2.1

→  23.9 m²


∴ The cost of plastering the wall per m² is 10.


The rate of plastering the wall 23.9 per m² = 10 × 23.9

                                                                       = 239.

The rate of plastering the wall 23.9 per m² is 239.


Hope this helps u


Be brainly


shreya190105: Hi
Similar questions