a door frame of dimension 6m×3.5m is fixed on wall of dimension 12m ×11m find the total charges for painting the wall if the labour charges for painting 1m square of the wall at rupees 4.50
Answers
Answer:
$235
Step-by-step explanation:
Area of the wall = length of the wall × breadth of the wall
= 10 × 10
=100m2
Now, here we have the area of the wall as 100 sq. meters.
Further, now let us calculate the area of the door-frame which occupies 3m × 2m of the space on the wall.
Area of the door frame = length of the door-frame × breadth of the door-frame
= 3×2
= 6m2
Here, we have the area of the door frame as 6 sq. meters.
Now to find the area which needs to be painted, subtract the area of the door-frame from the area of the wall.
Area which needs to be painted = Area of the wall – Area of the door-frame
= 100 – 6
= 94
Therefore, we found out that the area which needs to be painted is 94m2.
Now, the next step is to find the total labour charges required for painting the wall. Here, we have the labour charges for painting 1m2 is Rs. 2.50.
Therefore, let us find the labour charges to paint 94m2. Let us consider the total labour charges for painting the wall as ‘x’.
1 = 2.50
94 = x
x = 94×2.50
= 235
Step-by-step explanation:
Area = 6*3.5(Door Frame)
= 21m square
Area = 12*11 (Wall)
= 132m square
Therefore, 132-21 = 111m square
If 1m square = 4.50 Rs
111m square = 499.50 Rs
Answer:
The charges are 499.5 Rs