Math, asked by kshrd8166, 1 year ago

A door frame of dimensions 2m by 1.5 m is fixed on the wall of dimensions 12 m by 8m find the cost of painting the front of the wall if the rate of painting 1m square of wall is ₹20

Answers

Answered by himanshukumar14185
5

Total area of wall = 12×8m^2

=96m^

Then area of door frame. = 2×1.5m^2

= 3m^2

Remaining area of wall = 96m^2-3m^2

= 93m^2

Cost of painting wall 1m^2 = Rs 20

So cost of painting wall 93m^2 = Rs 20× 93

= Rs 1860 ans.


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