Math, asked by Anonymous, 3 months ago

A door frame of dimensions 4 m× 5 m is fixed on the wall of dimension 11 m ×11 m. Find the total labour charges for painting the wall if the labour charges for painting 1 m2 of the wall is RS. 2.50.



a.₹ 20


b.₹ 350


c.₹ 300


d. ₹ 252.50​

Answers

Answered by Anonymous
4

Answer:

Dimension of Door = 4m × 5m

Area = Length × Breadth

= 4m × 5m

= 20m²

Dimention of wall = 11m × 11m

Area = Side × Side

= 11 × 11

= 121m²

Area left for painting = Area of Wall-Area of Door

= 121m² - 20m²

= 101m²

Cost for painting 1m² = 2.50

Then,

Cost for painting 101m² = 101×2.50

= 252.50

Step-by-step explanation:

Hope it Helps uh!

Answered by ELECTROBRAINY
0

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DIMENSIONS OF WALL :- 11× 11= 121m2

DIMENSIONS OF DOOR:- 4×5= 20m²

AREA OF WALL TO BE PAINTED:- 121-20= 101m²

PER m²:- Rs. 2.50

=> TOTAL COST :- 101×2.50= 252.50

HENCE THE ANSWER IS 252.50

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