Question

A door is pushed open by applying a force of 50 N at a point 50 cm from the hinges. what is the moment of the force? 0.25 Nm 2.5 Nm 25 Nm w 2500 Nm.​

Answer 1

Answer:

Center of mass

Explanation:

Moment Of force = R × F

= 0.5 m × 50 N

I = 25 N-m

Option C

Answer 2

Given

• Perpendicular Distance = 50 cm
• Force = 5 N

To Find

• Moment of force

Solution

☯ τ = Fd

• Where F is the force applied and D is the perpendicular distance from the fixed point

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✭ According to the Question :

➞ τ = Fd

• Force = 50 N
• Distance = 50 cm = 50/100 = 0.5 m

➞ τ = 50 × 0.5 m

➞ τ = 25 Nm

∴ The answer is Option C