Question

A door of dimension 2m*1.2m*0.06m is acted upon by a certain force due to air inside the room. Whose pressure is 10^5pa the magnitude of the force in

Answer 1

Given:

A door of dimension 2m*1.2m*0.06m is acted upon by a certain force due to air inside the room.

To find:

Force acting on the door.

Calculation:

Pressure is a physical quantity describing the distribution of force over a surface area , hence it is calculated as force divided by the surface area.

$\boxed{ \bf{pressure = \dfrac{force}{area} }}$

$= > \rm{ {10}^{5} = \dfrac{force}{2 \times 1.2} }$

$= > \rm{ {10}^{5} = \dfrac{force}{2.4} }$

$= > \rm{force = 2.4 \times {10}^{5} \: N }$

So, final answer is:

$\boxed{\rm{force = 2.4 \times {10}^{5} \: N }}$