Math, asked by Harshpratap, 1 year ago

a door of length 2.2 metre and breadth 0.9 M is fitted in a wall. the dimensions of the wall are 5 M and 3.5 M find the cost of whitewashing the wall at rupees 35 per square metre

Answers

Answered by Anonymous
27
hello frnd!

here's ur answer...

given \: the \: length \: of \: the \: door \: is \: 2.2m \\ and \: breadth \: of \: the \: door \: is \: 0.9m \\ \\ hence \: area \: of \: the \: door = length \times breadth \\ = 2.2 \times 0.9 \\ = 1.98 {m}^{2} \\ \\ given \: the \: length \: of \: the \: wall \: is \: 5m \: and \\ breadth \: is \: 3.5m \\ \\ area \: of \: the \: wall \: excluding \: door \\ = length \times breadth - 1.98 \\ = (5 \times 3.5) - 1.98 \\ = 17.5 - 1.98 \\ = 15.52 {m}^{2} \\ \\ cost \: of \: whitewashing \: the \: wall \: if \: per \\ {m}^{2} costs \: rupees \: 35 = 15.52 \times 32 \\ = rupees \: 496.64 \\ \\ hope \: this \: helps \: u.....

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