Question

A door of length 2 m and breadth I m is fitted in a wall. The length of the
wall is 4.5 m and the breadth is 3.6 m . Find the cost of white
washing the wall, if the rate of white washing the wall is 20 per m².


❤Pls give the answer ❤❤❤❤❤❤❤​

Answer 1

Answer:

Step-by-step explanation:

Area of wall= 4.5x3.6 =16.2

Area of door= 2x1=2

Thus,

Area of wall to be white washed= 16.2-2= 14.2m^2

Cost= 14.2x20

284

Answer 2

The dimensions of the door are:

• Length (l₁) = 1 m.
• Breadth (b₁) = 3.6 m.

The dimensions of the wall are:

• Length (l₂) = 4.5 m.
• Breadth (b₂) = 3.6 m.

$\mathcal{\green{\underline{\blue{TO \:\: FIND:}}}}$

• The cost of whitewashing the wall, which is 20 per m².

$\mathcal{\green{\underline{\blue{SOLUTION:}}}}$

Let's draw the given situation ( I used ms paint)

Now, we need to find the area of the wall excluding the door so that we can  find the cost.

$\bf Area \:\: of \:\: ABCD:$

$\bf \to lenght \times breadth$

$\to \bf (2 \times 1)m^2$

$\to \bf 2m^2$

$\bf{Area \:\: of \:\: EHGF:}$

$\to \bf Lenght \times breadth$

$\bf \to (3.6 \times 4.5)m^2$

$\to \bf 16.2m^2.$

⇒Then, to find the area excluding the door:

$\bf {Required \:\: area = Area \:\: of \:\: EHGF - Area \:\: of \:\: ABCD}$

$\bf {Required \:\: area = 16.2 - 2}$

$\bf{Required \:\: area = 14.2m^2}$

Now, white-washing is ₹20 per m². Thus:

$\bf {Required \:\: cost = cost \:\: of \:\: 1m^2 \times total \:\: area}$

$\bf Required \:\: cost = 20 \times 14.2$

$\bf Required \:\: cost = 284rs.$

COST REQUIRED = ₹284.

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$\huge\star\:\:{\orange{\underline{\pink{\mathbf{HOPE \:\: THIS \:\: HELPS \: :D }}}}}$