Question

a door of length 2m and breadth 1m is fitted in a wall. the length of a wall is 4.5m and breadth is 3.6m. find tje cist of white washing the wall, if the rate of white washing the wall is 20 rs per m^2

Answer 1

Given,
Length of door=2 m
Breadth of door=1 m
Length of wall=4.5 m
Breadth of wall=3.6 m
To find,
Cost of whitewashing the wall
ATQ,
Cost of whitewashing=Area of wall to be white washed×Cost per m²
Now,
Area of wall=Length×Breadth
=4.5×3.6
=16.2 m²
Again,
Area of door=Length×Breadth
=2×1
=2 m²
Now,
Area of wall to be whitewashed=
Area of wall-Area of door=16.2-2=14.2 m²
Now,
Cost of whitewashing=Area of wall to be whitewashed×Cost per m²
=14.2×20
=₹ 284

Hope this helps you!

Answer 2

Answer:

Answer:

Given:

Length of wall = 4.5m

Length of wall = 4.5mBreadth of wall = 3.6m

Length of wall = 4.5mBreadth of wall = 3.6mLength of door = 2m

Length of wall = 4.5mBreadth of wall = 3.6mLength of door = 2mm Breadth door = 1m

To Find :

Area on the wall to be painted and what will be the cost at the rate of ruppes

${ \sf\bold\blue{20 \: per \: {m}^{2}}}$

$\begin{gathered} \huge{\green{Point \: to \: focus}} \\ \end{gathered}$

$\: \: {\sf{\red{area \: to \: painted = area \: of \: wall -area \: of \: door }}}$

$\begin{gathered}{ \sf{\red{area \: of \: wall = length \times breadth}}} \\ { \sf{\red{area \: of \: wall = 4.5\times 3.6}}} \\ { \sf{\red{area \: of \: wall = 16.2m²}}} \end{gathered}$

$\begin{gathered}{ \sf{\red{area \: of \: door = length \times breadth}}} \\ { \sf{\red{area \: of \: door= 2m\times 1m}}} \\ { \sf{\red{area \: of \:door \: =2m²}}} \\ { \sf{\red{area \: of \: wall \: to \: painted=16.2 {m}^{2} - 2m² = 14. {m}^{2} }}} \\ { \sf{\red{rate \: of \: painting \: 14.2 {m}^{2} =14.2m² \times 20 = 284}}} \\ \end{gathered}$