Question

- A door of length 2m and breadth Im
is fitted in a wall. The length of the
wall is 4.5m and the breadth is 3.6m
[fig 11.6). Find the cost of white
washing the wall, if the rate of white
washing the wall is 20 per m².​

Answer 1

Answer:

answer is 284

Step-by-step explanation:

area of wall to be whitewashed = area of wall -

area of door

= [3.6*4.5] - [2*1]

= 16.2 - 2

=14.2

cost of whitewashing per m^2 = 20

cost of whitewashing of 14.2 m^2 = 20*14.2 = 284

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Answer 2

Answer:

Given:

Length of wall = 4.5m

Length of wall = 4.5mBreadth of wall = 3.6m

Length of wall = 4.5mBreadth of wall = 3.6mLength of door = 2m

Length of wall = 4.5mBreadth of wall = 3.6mLength of door = 2mm Breadth door = 1m

To Find :

Area on the wall to be painted and what will be the cost at the rate of ruppes

${ \sf\bold\blue{20 \: per \: {m}^{2}}}$

$\begin{gathered} \huge{\green{Point \: to \: focus}} \\ \end{gathered}$

$\: \: {\sf{\red{area \: to \: painted = area \: of \: wall -area \: of \: door }}}$

$\begin{gathered}{ \sf{\red{area \: of \: wall = length \times breadth}}} \\ { \sf{\red{area \: of \: wall = 4.5\times 3.6}}} \\ { \sf{\red{area \: of \: wall = 16.2m²}}} \end{gathered}$

$\begin{gathered}{ \sf{\red{area \: of \: door = length \times breadth}}} \\ { \sf{\red{area \: of \: door= 2m\times 1m}}} \\ { \sf{\red{area \: of \:door \: =2m²}}} \\ { \sf{\red{area \: of \: wall \: to \: painted=16.2 {m}^{2} - 2m² = 14. {m}^{2} }}} \\ { \sf{\red{rate \: of \: painting \: 14.2 {m}^{2} =14.2m² \times 20 = 284}}} \\ \end{gathered}$