A door of length 3 m and breadth 2 m
is fitted in a wall. The length of the
wall is 20 m and the breadth is 8 m.
Find the cost of white washing the wall,
if the rate of white washing the wall is
8 per m
m?
Answers
Answered by
8
Answer:
white washing area = wall's area - door's area=
= 20×8m²-3×2m²
= 160m²-6m²
= 154m²
1m² white washing cost = ₹8
154m² white washing cost = ₹8×154= ₹1232
Answered by
5
The given
a door length =3m
and its breath = 2m
fitted in a wall
wall length =20m
its breath = 8m
Area of wall = l× b
20× 8
160m^2
wall Area = 160m^2
Now area of door = l×b
3×2
6m^2
door area = 6m^2
remain area of wall for white washing
= area of wall - area of door
= 160 - 6
= 154m^2
rate of white washing
1m^2 rate = 8 rupees
so
154 m^2 rate = 8× 154
= 1232 rupees answer
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