Question

a door of length 4m and breadth 3m is fixed in the wall. the length of the walls is 15.4m and breadth is 12.6m . find the remaining area of the wall.
also find the cost of white washing the wall at the rate of Rs 30 per m2
​

Answer 1

Given data :

• A door of length 4 m and breadth 3 m is fixed in the wall.
• The length of the walls is 15.4 m and breadth is 12.6 m.
• The cost of white washing the wall at the rate of Rs 30 per m².

To find : The remaining area of the wall and The cost of white washing.

Solution : Let, shape of the door and wall be rectangular.

Now, here according to given,

• Length of the door = 4 m
• Breadth of the door = 3 m

and

• Length of the wall = 15.4 m
• Breadth of the wall = 12.6 m

Firstly we have to find area of the door,

⟹ Area of the (rectangular) door

= Length * Breadth

⟹ Area of the (rectangular) door

= 4 * 3

⟹ Area of the (rectangular) door

= 12 m²

Similarly, to find area of the wall

⟹ Area of the (rectangular) wall

= Length * Breadth

⟹ Area of the (rectangular) wall

= 15.4 * 12.6

⟹ Area of the (rectangular) wall

= 194.04 m²

Now, to find the remaining area of the wall after putting the door in it;

⟹ Remaining area of the wall

= Area of the wall - Area of the door

⟹ Remaining area of the wall

= 194.04 - 12

⟹ Remaining area of the wall

= 182.04 m²

Now, to find the cost of white washing the wall;

⟹ Cost of white washing the wall

= Remaining area of the wall * Rate of washing at Rs per m².

⟹ Cost of white washing the wall

= 182.04 * 30

⟹ Cost of white washing the wall

= Rs 5461.2

Answer : Remaining area of the wall is 182.04 m² and cost of white washing the wall is Rs 5461.2

Learn more : A carpet is placed in the middle of a floor of a room 15 m long and 12 m broad so that it leavesa uniform width of 1 met...

https://brainly.in/question/38815723?

The sum of the areas of two squares is 400 sq.m. If the difference between their perimeters is 16 m, find the sides of t...

https://brainly.in/question/15920840?

Answer 2

Step-by-step explanation:

$\bigstar\underline{\large \underline \frak{Given}}$

• Length and breadth of door = 4m and 3m
• Length and breadth of walls = 15,4m and 12.6m
• Cost of white washing the wall per m² = Rs.30

$\blue{\bigstar\underline{\large \underline \frak{to \: find \: }}}$

• Find remaining area of wall.
• And cost of white washing the walls

$\bigstar \large \underline\red{ \underline{ \frak{formula \: used}}}$

• Area of door = length × breadth
• Area of wall = length × breadth

$\green{\bigstar\underline{\large \underline \frak{solution}}}$

First we have to find area of door = length × breadth

$\begin{gathered}\frak{we\;have}\begin{cases}\sf{\:\; \: Length = \bf{4\;m}}\\\sf{ \: \: \: Breadth = \bf{3 \;m}}\sf{ }\end{cases}\end{gathered}$

$\qquad \qquad \twoheadrightarrow \sf \: length \times breadth \\ \\ \qquad \qquad \twoheadrightarrow \sf \: 4 \times 3 \\ \\ \qquad \qquad \twoheadrightarrow \frak{ 12\: {m}^{2} }$

Now we find area of walls = length × breadth

$\begin{gathered}\frak{we\;have}\begin{cases}\sf{\:\; \: Length = \bf{15.4\;m}}\\\sf{ \: \: \: Breadth = \bf{12.6 \;m}}\end{cases}\end{gathered}$

$\qquad \qquad \qquad \twoheadrightarrow \sf \: length \times breadth$

$\\ \qquad \qquad \qquad \twoheadrightarrow \sf15.4 \times 12.6 \\ \\ \qquad \qquad \qquad \twoheadrightarrow \frak{194.04m {}^{2} }$

The remaining area of walls = area of door - area of walls

$\qquad \qquad \qquad \twoheadrightarrow \sf12 - 194.04 \\ \\ \qquad \qquad \qquad \boxed{ \twoheadrightarrow \frak{ {182.04 \: m}^{2} }}$

Now,

The cost of white washing 1 metre = Rs.30 per m²

The cost of white washing 182.04m² = Rs. ( 182.04× 30) = Rs. 5461.2

Hence the cost of white washing the wall is Rs. 5461.2