Question

A door of length 5 M and breadth 2m is fitted in a wall. The length of wall is 6.5 M and breadth 4.5 m. Find the cost of whitewashing the wall , if the rate of whitewashing the wall is rupees 50 per metre square

Answer 1

ANSWER:

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Length of the door =5m

Breadth of the door =2m

We will first find the area of the door and also the area of the wall respectively.

So,

$area \: of \: the \: door = l \times b.......(where \: l = length \: = 5m \: b = breadth = 2m)$
$area \: of \: the \: door = 5 \times 2 = 10 {m}^{2}$
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Length of the wall=6.5m

Breadth of the wall =4.5m

Now,

$area \: of \: the \: wall = l \times b.....(where \: l = length = 6.5m \: and \: b = breadth = 4.5m)$

$area \: of \: the \: wall = (6.5 \times 4.5)m = 29.25 {m}^{2}$

So , area of wall to wash,

$= 29.5 - 2 = 27.5 {m}^{2}$

So, the rate of white washing 

=27.5×50
=Rs 1,375.

Answer 2

$\huge\underline{\bold{\red{Answer\::}}}$

$\textbf{length of door = 5m}$

$\textbf{breadth of door = 2m}$

$\textbf{Area of door = l x b}$

$\textbf{5 x 2 = 10}$ ${m}^{2}$

$\textbf{length of wall = 6.5m}$

$\textbf{breadth of wall = 4.5m}$

$\textbf{Area of wall = l x b}$

$\textbf{4.5 x 6.5 = 29.25}$ ${m}^{2}$

Now...

$\textbf{Area for whitewashing = 29.25 - 10}$

[Area of wall - Area of door]

= $\textbf{19.25}$ ${m}^{2}$

$\textbf{Rate of Whitewashing the wall is}$ $\textbf{Rs. 50}$

So...

$\textbf{19.25\:times\:50}$

$\textbf{\red{962.5\:Rs.}}$