a door of width 6m has an arch of height 2m find it's radius
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Let Q be the centre o the arch. join AQ and PQ
Let PQ = x cm and AQ = QB = x + 2
In triangle QAP, by Pythagoras theorem,
AP2 = AQ2 + PQ2
(x + 2)2 = x2 + 32
x2 + 4x + 4 = x2 + 9
4x + 4 = 9
4x = 9 – 4 = 5
x = 5/4 = 1.25 cm
Therefore, radius of the arch = x + 2 = 1.25 + 2 = 3.25 cm
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