Question

A double connex lens has radii of curvature of 1m&2m .What
should be the refractive index so that focal length of the lens
is 5ocm?​

Answer 1

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Given:-

R1 = 1m = 10cm

R2 = 2 m = 20cm

f = 50cm

n = ?

Using the lens formula maker

$\frac{1}{f} = (n - 1)( \frac{1}{r1} ) - ( \frac{1}{r2} )$

$\frac{1}{50} = (n - 1)( \frac{1}{10} - \frac{1}{20} )$

Solving the above equation , we get

Refractive index , n = 1.13

Answer 2

Answer:

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