Question

a double convex lens has 2 surface of equal radius R and refarctive index n= 1.5 find the focal length​

Answer 1

Answer:

1/f=(n-1)(1/R1+1/R2)

n=1.5

R1=R2=R

1/f=(1.5-1)(1/R+1/R)

1/f=(0.5)(1+1/R)

1/f=1/2(2/R)

1/f=1/R

f=R

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Answer 2

Answer:

hey mate

Explanation:

1/f=(n-1)(1/R1+1/R2)

n=1.5

R1=R2=R

1/f=(1.5-1)(1/R+1/R)

1/f=(0.5)(1+1/R)

1/f=1/2(2/R)

1/f=1/R

f=R