Question

A double convex lens made of glass of refractive index 1.60 has both radii of curvature 30 cm each. Find the focal

length of the lens. If an object is placed at a distance of 15 cm from this lens, find the position of the image formed. ?​

Answer 1

Explanation:

I think it's answer ...........

Answer 2

Therefore, image distance from the lens is 37.5 behind the lens(  the same side where object is placed).

Explanation:

We know by Lens Maker's Formula :

$\dfrac{1}{f}=(\mu-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})$

Here, $R_1=30\ cm \ , \ R_2=-30\ cm.$

Also, $\mu=1.6$

Putting all these value in above equation we get,

$\dfrac{1}{f}=(1.6-1)(\dfrac{1}{30}-(\dfrac{-1}{30}))=\dfrac{1}{25}$

Therefore, $f=25\ cm.$

Now, object position, u =  15 cm.

We know, Lens formula :

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

Putting values of u and f in above equation.

We get,

v = -37.5 cm.

Hence, this is the required solution.

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