Question

A double convex lens of f=6 cm is made of glass of refractive index 1.5 .the radius of curvature of the surface which is doubled that of other surface will be

Answer 1

answer : 4.5cm

explanation : focal length of convex lens, f = 6 cm

refractive index of lens , μ = 1.5

use formula,

$\frac{1}{f}=(\mu-1)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$

a/c to question, the radius of curvature of the surface is doubled of the other surface.

so, $R_1=R$, $R_2=-2R$

so, 1/f = (μ - 1) [ 1/R + 1/2R ]

or, 1/f = 3(μ - 1)/2R

or, R = 3(μ - 1)f/2

putting f = 6 and μ = 1.5

⇒ R = {3 × (1.5 - 1) × 6}/2 = 9 × 0.5 = 4.5cm

hence, radius of the curvature is 4.5cm

Answer 2

Answer:

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Explanation:

All the steps are explained and

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