A double convex lens of refractive index µ1 is immersed in a liquid of refractive index µ2. The lens will act as transparent plane sheet when (a) µ1 = µ2 (b) µ1 > µ2 (c) µ1 < µ2 (d) µ1 = 1μ2
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Given :
Refractive index of double covex lens = μ₁
Refractive index of liquid = μ₂
To Find :
The relation between μ₁ and μ₂
Solution :
- Let us assume light rays are travelling through the liquid medium and also the double convex lens
- If μ₁ < μ₂, the lens will become diverging
- If μ₁ > μ₂, the lens will become converging
- For the lens to act as transparent plane sheet μ₁ = μ₂
The relation between μ₁ and μ₂ is μ₁ = μ₂
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