Question

A doubly ionized lithium atom is like h aton withz3. Finr the wavelength

Answer 1

Hello,

H has an atomic number of 3 according to the question

So, According to the question,

${Li^{2+}}$ = H with atomic number 3

E = ${-R_{H}}$ $\frac{1}{n^{2}}$

Here,

n = 3

${R_{H}}$ = ${2.18* 10^{-18}}$

Substituting the values, we get

E = ${2.18* 10^{-18}}$ × $\frac{1}{3^{2}}$

E =  ${2.18* 10^{-18}}$ × $\frac{1}{9}$

E = 0.242 × ${10^{-18}}$

Frequency = E/h

                =  0.242 × ${10^{-18}}$ / 6.626 × ${10^{-34}}$

                 =  0.0365 × ${10^{16}}$

Wavelength = c/frequency

                     = 3 × ${10^{8}}$ /  0.0365 × ${10^{16}}$

                      = 82.19 × ${10^{-8}}$