Question

a dragster in a race accelerated from stop to 60m/s by the time it reached the finish line. the dragster moved in a straight line and traveled from the starting line to finish line in 8.0 sec. what was the acceleration of the dragster

Answer 1

Given :-

v = 60m/s

u = 0

t = 8 s

• a = ?

Solution :-

• We know that, a = Δv/t

⇒ a = (60 -0)/8

⇒ a = 60/8

⇒ a = 7.5

Final Answer ⇒ a = 7.5 m/s²

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Answer 2

Acceleration = $7.5 m/s^{2} .$

• Acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated.
• Because the direction is always shifting, motion on a circle accelerates even while the speed is constant. Both effects add to the acceleration for all other types of motion.
• It is a vector quantity because acceleration has both a magnitude and a direction.
• Another vector quantity is velocity. The velocity vector change during a certain period of time, divided by that period of time, is the definition of acceleration.

Here, according to the given information, we are given that,

The final velocity (v) = 60 m/s.

The initial velocity (u) = 0 m/s.

Time (t) = 8.0 sec.

Then,

Acceleration = $\frac{v-u}{t}$

Or, Acceleration = $\frac{60-0}{8} = 7.5 m/s^{2} .$

Hence, Acceleration = $7.5 m/s^{2} .$

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